General Chemistry · Stoichiometry

Limiting Reactant —
N₂ + 3H₂ → 2NH₃ Mixing Box

The number of ammonia molecules formed is not an input. It follows from molecules pairing up in the coefficient (mole) ratio. First predict, then change the molecule numbers and observe, and finally check yourself.

Key summary: (1) The coefficients in N₂ + 3H₂ → 2NH₃ give the ratio in which molecules react (1:3:2). (2) When one reactant runs out, the reaction stops and the other reactant is left over. (3) Set the numbers in the box, press [Run reaction], and see which reactant runs out first.

Learning objectives After this activity you can …
explain, with a reason, whether the limiting reactant is decided by the number of molecules or by the coefficient ratio.
identify the limiting reactant from the 1:3 mole ratio for given numbers of N₂ and H₂.
calculate the NH₃ formed and the leftover (excess) reactant from the coefficient ratio.
Progress 0% · Predict → Observe → Check → Complete

Before reaction (mixing box)

BEFORE · N₂ + H₂
N₂ / H₂ added—

After reaction (complete)

AFTER · NH₃ + LEFTOVER
NH₃ molecules formed—
Entry check Before you start — prerequisites and key terms

In the equation N₂ + 3H₂ → 2NH₃, how many H₂ molecules does one N₂ molecule need to react completely?

123
Key terms

Mole: a counting unit for particles (here we compare numbers of molecules directly). · Coefficient ratio (mole ratio): the ratio of the coefficients in the equation, N₂:H₂:NH₃ = 1:3:2. · Batch: how many complete reaction sets a reactant can supply (number ÷ its coefficient). · Limiting reactant: the reactant that runs out first relative to the coefficient ratio and stops the reaction. · Excess reactant: the reactant that is not used up and is left over.

Predict Think first, before you observe

You put 2 N₂ and 3 H₂ molecules into the box (N₂ + 3H₂ → 2NH₃). Which is the limiting reactant?

Nitrogen, N₂ Hydrogen, H₂ Both run out at the same time
ConfidenceMedium
The explanation opens after you lock in a prediction
010
030
Atom labels
N₂ (nitrogen, blue) H₂ (hydrogen, white) NH₃ (ammonia, green = product)

The explanation opens after you lock in a prediction.

Key idea 1 · Limiting reactant = the one that is short relative to the coefficient ratio

The limiting reactant is not simply the one with fewer molecules. Compare the reactants after dividing by the coefficients (N₂:H₂ = 1:3). Example: with N₂ = 2 and H₂ = 3, N₂ gives 2 batches and H₂ gives 3 ÷ 3 = 1 batch. H₂ gives fewer batches, so H₂ is the limiting reactant and N₂ is left over.

N₂ + 3H₂ → 2NH₃
Batches: N₂ batches = N₂ | H₂ batches = H₂ ÷ 3 → the smaller one is limiting

Key idea 2 · NH₃ formed and leftover

N₂ that reacts = min(N₂, H₂÷3 rounded down). One N₂ gives two NH₃, so NH₃ formed = 2 × (N₂ that reacted). After the reaction, the limiting reactant is 0 and the other reactant is left over (excess). The same idea is used for nitrogen fertilizer: ammonia made from N₂ and H₂ is the starting point of most nitrogen fertilizers.

NH₃ = 2 × min(N₂, floor(H₂/3))
Limiting reactant used up to 0 | excess reactant left over
Check Formative check — pass all items to complete
Q1You add 2 N₂ and 3 H₂. Which is the limiting reactant? (N₂ + 3H₂ → 2NH₃)
Nitrogen, N₂ Hydrogen, H₂ No limiting reactant
Hint

Divide each reactant by its own coefficient (N₂÷1, H₂÷3) to get its batches, then compare. The smaller one is limiting.

Q2 · Hands-on taskAdjust the sliders and press [Run reaction] to reach the target state Then press [Check].
NH₃ formed now: — molecules
Q3For the given numbers of N₂ and H₂, how many NH₃ molecules form? (enter a whole number)
Hint

Compare the batches.

Q4 · Fill in the blankFill in the blank: The reactant that runs out first relative to the coefficient ratio and stops the reaction is called the [_____].
Hint

A two-word term: an adjective + "reactant".

Q5 · Apply (higher-order, not required for completion)You add 4 N₂ and 9 H₂ and let the reaction finish. Which pair of limiting reactant and leftover reactant is correct?
H₂ limiting · 1 N₂ left over N₂ limiting · H₂ left over H₂ limiting · nothing left over
Hint

Batches: N₂÷1 = 4, H₂÷3 = 3. Which is smaller? Then count how many N₂ react.

Reflect Reflect — metacognition · completion

My prediction: Not predicted yet

In one sentence, explain why the limiting reactant is not just "the one with the smaller amount" (key words: limiting reactant, mole ratio / coefficient ratio):

Going further (optional)

Set N₂ and H₂ to exactly 1:3 (for example N₂ 3, H₂ 9). Both are used up, with no limiting reactant and nothing left over. Then NH₃ formed = 2 × N₂. In the industrial Haber–Bosch process, H₂ is usually added in excess so that as much N₂ as possible reacts.

Apply Use the idea in a new context (not required for completion)

Transfer task: one sandwich needs 2 slices of bread and 1 patty. You have 10 slices of bread and 3 patties. How many sandwiches can you make, and what is left over? Explain in one sentence using the idea of limiting reactant and coefficient ratio.

COMPLETE · Completed — all checks passed.

Worksheet — Limiting reactant: N₂ + 3H₂ → 2NH₃

Name ________ Class ________ Date ________

1. Predict — With 2 N₂ and 3 H₂, which is the limiting reactant? (N₂ / H₂ / none)

2. Observe — For each case, fill in the batches, the limiting reactant, the NH₃ formed and the leftover.

N₂=2, H₂=3 → limiting:____ NH₃ formed:____ leftover:____

N₂=3, H₂=12 → limiting:____ NH₃ formed:____ leftover:____

2-1. Calculate — How many NH₃ molecules form from the given N₂ and H₂? Answer: ______

3. Conclusion — In one line, why is the limiting reactant not just "the one with the smaller amount"?

4. Fill in the blank — The reactant that runs out first relative to the coefficient ratio is called the [_____].

QR / link: the simulation address given by your teacher

Teacher notes — open the lesson plan

Lesson plan · 5E phase and time

  • Explore · Explain stage. 10–15 min after the introduction.
  • Works as a whole-class demo (projector, ?mode=teacher) or as individual work on one device per student.

Demo in 3 steps

  • (1) N₂=2, H₂=6 → both used up, NH₃=4 (exact 1:3 mole ratio).
  • (2) N₂=2, H₂=3 → H₂ limiting, NH₃=2, 1 N₂ left over (N₂ has fewer molecules but is NOT limiting).
  • (3) N₂=3, H₂=12 → N₂ limiting, NH₃=6, 3 H₂ left over.

3 key questions

  • "There are fewer N₂ molecules. So why does H₂ run out first?"
  • "Which reactant decides the number of NH₃ molecules formed?"
  • "The reaction has stopped. Why is one kind of molecule still there?"

Common misconceptions

  • MC-lim-01: "Limiting reactant = the one with fewer molecules" → it is the one with fewer batches after dividing by the coefficient. With N₂=2, H₂=3, H₂ is limiting.
  • MC-lim-02: "Product formed = amount of limiting reactant" → use the coefficient ratio. NH₃ formed = 2 × (N₂ that reacted).

Answer key (by level, Q2 · Q3 · Q4)

  • Basic: Q2 4 NH₃ (e.g. N₂ 2 · H₂ 6) · Q3 N₂ 2 · H₂ 9 → 4 (N₂ limiting) · Q4 limiting reactant
  • Standard: Q2 H₂ limiting · 6 NH₃ (e.g. N₂ 4 · H₂ 9) · Q3 N₂ 3 · H₂ 12 → 6 (N₂ limiting) · Q4 limiting reactant
  • Advanced: Q2 H₂ limiting · 1 N₂ left · 8 NH₃ (N₂ 5 · H₂ 12–14) · Q3 N₂ 5 · H₂ 12 → 8 (H₂ limiting; the "fewer molecules" misconception gives 10) · Q4 excess reactant
  • Q5 (apply): H₂ limiting, 3 N₂ react, 1 N₂ left over.

Prerequisites

  • Coefficients in a chemical equation and balancing; the mole and mole ratio.
University general chemistry · Stoichiometry General Chemistry Engine E1 particle / molecular-model box Verified: chemistry · learning design · teacher (3-way, 2026-06-17)
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